F(x)=2x^2-3x+7F(2.5)

Solution for F(x)=2x^2-3x+7F(2.5) equation:

(F)=2F^2-3F+7(2.5)

We move all terms to the left:

(F)-(2F^2-3F+7(2.5))=0


We calculate terms in parentheses: -(2F^2-3F+7(2.5)), so:

2F^2-3F+7(2.5)

We add all the numbers together, and all the variables

2F^2-3F+17.5

Back to the equation:

-(2F^2-3F+17.5)


We get rid of parentheses

-2F^2+F+3F-17.5=0

We add all the numbers together, and all the variables

-2F^2+4F-17.5=0

a = -2; b = 4; c = -17.5;
Δ = b2-4ac
Δ = 42-4·(-2)·(-17.5)
Δ = -124
Delta is less than zero, so there is no solution for the equation